![]() ![]() This gives a resulting hole size of 9.57mm diameter which is pretty damn close to the 9.56mm that you measured.ġ. If you put your figures into the formula in reverse it tells you the size that the hole will end up if you make no adjustment. Also, the slight inaccuracies in the outside dimensions are same no matter the size of the part, so I know it's not a steps per mm issue. The height of the part is almost perfect. The 20mm dimension printed at 20.18mm and the peg printed at 10.16mm. I just printed a test piece that is a 20mm circle with a 10mm peg sticking off and a corresponding piece that has a 10mm hole for the peg to fit in. The shrinkage makes sense, but I have a friend with the same printer and the same brand of filament, and his come out perfect with no compensation for shrinkage. These figures were for PLA, and as I understand it, they take into account various factors including the fact that the inside of the hole is unrestrained against shrinkage. ![]() They suggested that where X mm was the required diameter of the hole then Y mm was the dimension needed to achieve it and that:Ī) for vertical holes Y = 1.0155X + 0.2795 mmī) for horizontal holes Y = 0.9927X + 0.3602 mm There is a forular to calculate the needed diamater as follows ![]() Holes are made up of many straight lines rather than pure arcs. Holes allways come out smaller than what you specify,due to shrinkage of the plastic and the fact that ![]()
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